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balu736 [363]
3 years ago
13

How do you solve this equation?

Mathematics
1 answer:
Travka [436]3 years ago
7 0
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


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Answer:

The answer to your question is:  x = -1

Step-by-step explanation:

Data

slope of l = x

slope of m = x +2

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Process

If they are ⊥, then,     x + 2  = - 1/x

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6 0
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<u>Step-by-step explanation:</u>

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3 years ago
Start with the logistic equation dx dt kx(M−x). Suppose we modify our harvesting. That is we will only harvest an amount proport
Marina CMI [18]

Answer:

a) dx/dt = kx*(M - h/k - x)

Step-by-step explanation:

Given:

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                            dx/dt = kx*(M-x)

Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In  other  words  we  harvest hx per  unit  of  time  for  some h > 0

Find:

a) Construct the differential equation.  

b) Show that if kM > h, then the equation is still logistic.

c) What happens when kM < h?

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It can be simplified to:

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                              dx/dt = kx*(M_n  - x)  

Hence, This equation is logistic because M_n >0

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