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Dovator [93]
2 years ago
9

3/4x + 4/7y = 5/4x -1...solve for y​

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
5 0

Answer:

\frac{3}{4} x +  \frac{4}{7} y =  \frac{5}{4} x - 1 \\  \frac{4}{7} y =  \frac{5}{4} x - 1 - \frac{3}{4} x \\  \\  \frac{4}{7} y =  \frac{5x - 4 - 3x}{4}  \\  \frac{4}{7} y =  \frac{2x - 4}{4}  \\  \\ y = \frac{2x - 4}{4} \div   \frac{4}{7} \\ y =  \frac{2x - 4}{4} \times  \frac{7}{4}  \\  \\ y =  \frac{14x - 28}{16}  \\  \\ y =  \frac{14x}{16}  -  \frac{28}{16}

I hope I helped you^_^

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A number line going from 1 to 13. 1 dot is above 1. 3 dots are above 2. 1 dot is above 3. 3 dots are above 4. 1 dot is above 5.
aliina [53]

Answer:

Answer: C) The mean will increase more than the median, but both will increase.

Step-by-step explanation:

I got it right on the test review.

5 0
3 years ago
Read 2 more answers
2 Simplify -3(16 = 35+4)/5. Show your work.
Masteriza [31]

Answer:

-9

Step-by-step explanation:

Parentheses first:16-35+4 = -35+16+4 = -35+20 = -15

3(-15) = -45/5

-45 divided by 5 = -9

3 0
3 years ago
The function y = x 2 - 10x + 31 has a ____
katrin [286]

Answer:

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

Step-by-step explanation:

In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.

Given function is:

f(x) = x^2-10x+31

Taking first derivative

f'(x) = 2x-10

Now the first derivative has to be put equal to zero to find the critical value

2x-10 = 0\\2x = 10\\x = \frac{10}{2} = 5

The function has only one critical value which is 5.

Taking 2nd derivative

f''(x) =2

f''(5) = 2

As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5

The value can be found out by putting x=5 in the function

f(5) = (5)^2-10(5)+31\\=25-50+31\\=6

Hence,

<u>The function y = x 2 - 10x + 31 has a minimum  value of 6</u>

Hence,

Option B. minimum is correct for the first blank

Option C. 6 is correct for second blank.

8 0
3 years ago
Mr. Janson paid for admission to the high school football game for his family. He purchased 3 adult tickets and 2 student ticket
Vilka [71]

Answer: adult ticket : 5.50

Student ticket : 2.75

Step-by-step explanation:

8 0
3 years ago
It is given 5 and h + 1 are the roots of the quadratic equation x² + (k - 1)x - 5 = 0,where h and k are constant.Find the value
Liono4ka [1.6K]

Answer:

Hello,

<u>k=-3 and h=-2</u>

Step-by-step explanation:

5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\

h+1 is thus a root of x²+(-3-1)*x-5=0

x²-4x-5=0

x²+x-5x-5=0

x(x+1)-5(x+1)=0

(x+1)(x-5)=0

h+1=-1

<u>h=-2</u>

6 0
3 years ago
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