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Olenka [21]
3 years ago
15

Which statement is false

Mathematics
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer:

C

Step-by-step explanation:

measure BOA and measure COA are not congruent.

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Zane bought a pair of jeans that originally cost $56. He used a coupon for 25% off and paid 8% in sales tax. How much did he pay
sattari [20]

Answer:

$38.64

Step-by-step explanation:

so the equation needed to solve is $56*0.25 and that number is 14. Since it is a coupon you subtract 14 from 56 and end up with 42. Now multiply 0.08*42 and you got your sales tax, $3.36. now subtract that from 42 and you have your answer! Don't forget the dollar sign!

hope this helped! : )

5 0
3 years ago
WHY IS MATH SO COMPLICATED?!
Tomtit [17]
Closed dot on 53, arrow going to the right
6 0
3 years ago
Which one doesn’t belong? Why? Explain. please help me
My name is Ann [436]

Hi! So, the one that doesn't belong is a) y = 4x.

I think that this doesn't belong because every other option has a number after the variable (I forget the exact term for it but it's like +7, +4, and -1 for the rest of the options)

Please let me know how I can further help you :)

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5 0
3 years ago
Read 2 more answers
Giovanni justifies whether the expression –4x – 8 is equivalent to Negative 2 (x + 1) minus 2 (x + 3) by letting x = 3 in both e
Vladimir [108]

Answer:

When x = 3, the solutions to the expressions are–20 and –20

Step-by-step explanation:

–4(3) – 8   Multiply

-12 - 8       Subtract

-20

-2(3 + 1) - 2(3 + 3)     Simplify in the parentheses

-2(4) - 2(6)                 Multiply

-8 - 12                        Subtract

-20

               

6 0
3 years ago
Read 2 more answers
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
3 years ago
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