Answer:
The adult and the child ticket are both 8 dollars
Step-by-step explanation:
x =adult ticket price
y = child ticket price
I will assume you forget to put that they sold 2 child tickets on the second day
7x+5y=96 and 3x+2y= 40
I will use elimination. Multiply the first equation by 2 and the second equation by -5 to eliminate y
2(7x+5y)=96*2
14x + 10y = 192
The second equation
-5(3x+2y)= 40*-5
-15x -10y = -200
Add the equations together
14x + 10y = 192
-15x -10y = -200
------------------------
-x = -8
Multiply by -1
x = 8
Now we need to find y
3x+2y= 40
3(8) +2y = 40
24+2y = 40
Subtract 24 from each side
24-24 +2y = 40-24
2y = 16
Divide by 2
2y/2 =16/2
y =8
The adult and the child ticket are both 8 dollars
If these triangles are congruent, then side RS is congruent to side TV and that means that y = 4 - x. If y = 4-x, we can sub that into the next equation where side RV = side ST and 1 = 4x - y. If y = 4-x, we sub in accordingly to get 1 =4x - (4 - x). That simplifies to 1 = 4x - 4 + x which is, combining like terms, 5 = 5x. That means that x = 1. If x = 1, and y = 4 - x, then y = 4 - 1 and y = 3. There you go!
Answer:
13 square units
Step-by-step explanation:
We need to find the distance between the points using the
Pythagorean Theorem, a² + b² = c²
(3,6) and (6,5); 6 - 3 = 3 and 6 - 5 = 1
3² + 1² = c²
9 + 1 = c²
c = √10
(6,5) and (5,1); 6 - 5 = 1 and 5 - 1 = 4
1² + 4² = c²
1 + 16 = c²
c = √17
√17 + √10 = 13.038
