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3 years ago

I dont know how to write the question or answers

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

i think i think its B

Step-by-step explanation:

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Factor 4a^2-25. Please

Dmitrij [34]

Answer:

(2 a - 5) (2 a + 5)

Step-by-step explanation:

Factor the following:

4 a^2 - 25

4 a^2 - 25 = (2 a)^2 - 5^2:

(2 a)^2 - 5^2

Factor the difference of two squares. (2 a)^2 - 5^2 = (2 a - 5) (2 a + 5):

Answer: (2 a - 5) (2 a + 5)

8 0

3 years ago

Which of the following is the solution to 31 %-12 12?

stellarik [79]

Answer:

I think so, but don't lose sight

4 0

3 years ago

HELPPP!!!! Both questions are incredibly confusing to me !!!!!

Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT Reflexive property

<STR = <WTR A straight line having 1 rt angle actually has 2

ST = TU They are marked as equal

Triangle STR=Triangle WTR SAS

RS = RW Corresponding parts of = triangles are =

8x = 6x + 5 Subtract 6x from both sides

8x -6x = 6x - 6x + 5 Combine

2x = 5 Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW Reflexive

<UTW = STW Same reason as in 3. UtW is a right angle

UT = ST Given (the marking tells you so.

ΔUTW = ΔSTW SAS

UW = SW Corresponding parts of = triangles are =

SW = 8

7 0

2 years ago

If AD and BD are bisectors of CAB and CBA respectively. Find the sum of angles x and y.

olchik [2.2K]

The picture in the attached figure

step 1
we know that
It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.
Therefore,
x = ∠CAB/2 -----> equation 1
y = ∠CBA/2 -----> equation 2

step 2
In triangle ABC,
∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a triangle is 180°]
∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides
∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3
substitute equation 1 and equation 2 in equation 3
x+y=35

hence

the answer is
x+y =35°
⇒ x + y = 35° ...[From equation (1) and (2)]

5 0

3 years ago

Pleaseeeee help me i really need this

lisov135 [29]

Answer:

A for Circle=2pi*r and A for Square= b*h, then find the difference between the two

Step-by-step explanation:

7 0

2 years ago

I dont know how to write the question or answers​

I dont know how to write the question or answers