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Makovka662 [10]
2 years ago
7

W(a) = -2a – 4; Find w(-6)

Mathematics
2 answers:
jeyben [28]2 years ago
7 0

Answer:

w(-6) = 8

Step-by-step explanation:

w(a) = -2a – 4

Let a = -6

w(-6) = -2(-6) – 4

Multiply

      = 12 -4

Subtract

    = 8

Ray Of Light [21]2 years ago
5 0

Answer:

...

Step-by-step explanation:

w(a) = -2a - 4

w(-6) = <em>subsitute value</em> // -2(-6) - 4 = 12 - 4 = 8

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Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation
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Answer:

See explanation below

Step-by-step explanation:

<u>First we will solve the radical equation</u> (which I guess was problem 1),

Let's start by simplifying it:

3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4

Now we will solve the equation by squaring both sides of the equation:

\sqrt{6-x} =-4\\6-x=-4^{2} \\6-x=16\\-x=16-6\\-x=10\\x=-10

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8

This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

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2 years ago
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Katen [24]

Answer:

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What is the absolute value of the complex number -4-√2i?
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Hello : 
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