The scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
<h3>What is the scale factor from rectangle Q to rectangle R?</h3>
In geometry, the scale factor is a ratio of the resulting length to the initial length. Since the area of the square is equal to the square of its side length, then the scale factor is equal to:
k² = A' / A
k = √(A' / A)
Where:
- k - Scale factor
- A' - Area of the rectangle R.
- A - Area of the rectangle Q.
If we know that A = 2 and A' = 72, then the scale factor is:
k = √(72 / 2)
k = √36
k = 6
Then, the scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
To learn more on scale factors: brainly.com/question/22312172
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Answer:
Step-by-step explanation:
I assume that you mean
sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?
then this is equivalent to
[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1
let s evaluate it, we got
sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)
= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1
as cos2(x) + sin2(x) = 1
Answer: C. 10.2
Step-by-step explanation: because in decimal form 10.19803902 to the nearest is 10.2
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Answer:</u></h3>
Option: D
Horizontal stretching.
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Step-by-step explanation:</u></h3>
We have to find the effect on the graph of the function f(x)=2x when it is replaced by f(0.5 x).
We know that when a parent function f(x) is replaced by f(kx) then either the graph is stretched horizontally or shrinked horizontally.
if k>1 then the graph is shrinked horizontally.
if k<1 then the graph is stretched horizontally.
Hence here k=0.5<1 so the graph of the function is stretched horizontally.
