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Genrish500 [490]
3 years ago
15

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Mathematics
1 answer:
Kisachek [45]3 years ago
7 0
So, I'm going to break it down to help you understand it a bit more.

If it starts at (0,-2) and crosses through (1,0) that means it moved to the right once and up twice. Which means, that the slope will be 2. If it were one it would be to the right 1 up one, if it were 4 it would be to the right 1 up 4, and finally if it were 1/2 it would be to the right 2 up 1. 

So, your answer is C. or 2. 
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If the discriminant of an equation is zero, which of the following is true of the equation?​
White raven [17]

\sf Your \: question \: is \: incomplete. \:

______________________

\sf \: I \: believe \: this \: is \: the \: answer \: you \: wanted ⟹

\sf If  \: the  \: discriminant  \: of \:  an \:  equation \:  is  \: zero, \: then \\  \sf \: the \: equation \: will \: have \:\underline{ 1 \: real \: solution \: with \: real \: and \: equal \: roots}.

\boxed{ \sf{Explanation}}

\sf If \: discriminant \: of \: quadratic \: equation  \: ax^{2} + bx + c \: \\ \sf is \: b^{2} - 4ac = 0 \: then \: it \: will \: have \\ \sf↦\underline{1 \: real \: solution \: with \: real \: and \: equal \: roots.}

7 0
3 years ago
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I am Lyosha [343]

Answer:

Answer in explanation

Step-by-step explanation:

When we talk of compression of gases, what we are talking about is simply the reduction in the volume of the gases. When we compress a volume of a gas, we are looking at reducing the volume of the gas in question.

Now, let’s work through this. The postulate that works in this scenario is that postulate about the interaction between the gas molecules whether attractive or repulsive are negligible. This is the driving force that dictates the compressibility of gases.

Gases are termed compressible because the the negligible force of attraction or repulsion between them confers a kind of fluidity to these gases. It is this fluidity that makes it possible for gases to be compressible.

If it was that the attractive or repulsive forces are not negligible, they would have posed a difficulty that would be dependent on the strength of the compressive forces to overcome

7 0
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kakasveta [241]

Answer:

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.40C = $20

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Lubov Fominskaja [6]

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djyliett [7]

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If you divide \frac{8}{12} by 4 (both numerator and denominator)

You get \frac{2}{3} which is equivalent to the given ration

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