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3 years ago

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Mathematics

1 answer:

Kisachek [45]3 years ago

7 0

So, I'm going to break it down to help you understand it a bit more.

If it starts at (0,-2) and crosses through (1,0) that means it moved to the right once and up twice. Which means, that the slope will be 2. If it were one it would be to the right 1 up one, if it were 4 it would be to the right 1 up 4, and finally if it were 1/2 it would be to the right 2 up 1.

So, your answer is C. or 2.

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Is there such a thing as 0x, there's 5x, 6x, 19x, x etc., but 0x... just sound weird to me.

erastovalidia [21]

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3 years ago

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10x - 10y = 1 x = y - 3 solve the system of equations by substitution. a. (-29/20, 31/20) b. (1/2, 2/5) c. no solution d. coinci

Gekata [30.6K]

First you'd substitute x= y-3 in the first equation.

10(y-3) -10y= 1

10y - 30 -10y= 1

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3 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .