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VashaNatasha [74]

2 years ago

15

100 students in a classroom like iPhone or Samsung mobile or both mobile. Out kf them, 40 both mobiles. It the ratio of number o

f students who like iPhone and Samsung is 3:2, by using venn diagram, find the number of students who like iPhone?

1 answer:

ladessa [460]2 years ago

4 0

The number of students who like Iphone: 46

I hope that answers your question!

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Need help on math question thanks <br> A) 0.303 <br> B) 0.435 <br> C) 0.406<br> D) 0.154

Airida [17]

Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

<u>Explanation</u>:-

Given data

Brown Blue Hazel Green

Females 13 4 6 9

Males 10 2 9 12

<em>Let 'B' be the event of brown eyes </em>

<em>Total number of males n(M) = 33</em>

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>

<em></em> $P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$ <em></em>

<em>From table the brown eyes from males = 10</em>

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

<u>Final answer</u>:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

8 0

3 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

$1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297$

4 0

2 years ago

Help me it is below

Fofino [41]

I hope this helps you

7 0

3 years ago

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WILL GIVE BRAINLIEST TO ANSWER

Anika [276]

its x4 got it thanks give me brainliest

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3 years ago

What makes 83 cents ?

Sliva [168]

83 Cents = 2 Quarters, 1 Nickel, 4 Pennies.

Glad I Could Help, And Good Luck!

~AnonymousGiantsFan~

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3 years ago

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