Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
I'm not too sure about this one but if you find 3% of $200 you get 6 and if you multiply that by 2 ( for the 2 years ) you'll get ( A $12 )
Answer:
The area of the trapezoid is 
Step-by-step explanation:
we know that
The area of a isosceles trapezoid is equal to the area of two isosceles right triangles plus the area of a rectangle
step 1
<em>Find the area of the isosceles right triangle</em>
Remember that
In a isosceles right triangle the height is equal to the base of the triangle
we have
so
The area is equal to
substitute the values
step 2
Find the area of the rectangle
The area of the rectangle is equal to
we have
-----> is the height of the trapezoid
-----> the diagonal of the rectangle
Applying the Pythagoras Theorem
The area of the rectangle is
step 3
Find the area of the trapezoid
A Canadian postal code looks like this:
K1A 3B1 .
So you have: letter - digit - letter - digit - letter - digit .
The question doesn't say anything about restrictions on
which letters can be used, or restrictions on repeating letters
or digits within one postal code. So as far as we know, each
letter can be any one of 26, and each digit can be any one of 10.
The total number of possibilities would be
(26·10·26) · (10·26·10) = 17,576,000 .
In the real world, though, (or at least in Canada), Postal codes
don't include the letters D, F, I, O, Q or U, and the
first letter
does not use W or Z. When you work it out with these restrictions,
it means there's a theoretical limit of 7.2 million postal codes.
The practical limit is a bit lower, as Canada Post reserves some
codes for special functions, such as for test or promotional purposes.
One example is the code H0H 0H0 for Santa Claus ! Other special
codes are for sorting mail
bound for destinations outside Canada.
At the present time, there are a little over 830,000 active postal codes.
That's about 12% of the total possibilities, so there are still plenty of codes
left for expansion.
Answer:
The price per volleyball is $3.
Step-by-step explanation:
Divide $18 by 6 for the cost of each volleyball in which your final answer should be $3 per volleyball.
