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Sergeu [11.5K]
3 years ago
5

What are the missing coefficients for the chemical equation [ ] Ca + [ ] O2 → [ ] CaO

Chemistry
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

{ \sf{[ 2] Ca_{(s)} + [1 ] O_{2(g)} → [ 2] CaO _{(s)}}}

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What volume (mL) of concentrated solution of magnesium chloride (9.00 M) must be diluted to 350. mL to make a 2.75 M solution of
zalisa [80]

❤Answer

<u>Volume </u><u>of</u><u> 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL.</u>

⠀

⠀

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<u>We can use the </u><u>formula.</u><u> </u>

c1v1 =c2v2

<u>Where c1 is the concentration and v1 is volume of the concentrated </u><u>solution.</u><u> </u>

c2 is the concentration

and v2 is the volume of the diluted solution to be prepared

9.00 M x V1 = 2.75 M x 350 mL

V1 = 106.9 mL

<u>Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL</u><u>.</u>

3 0
2 years ago
How many grams of caffeine should we prepare in a 10 mL standard of 3 mm
Brut [27]

Answer:

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Explanation:

8 0
3 years ago
Read 2 more answers
For the chemical reaction, 2HCl + Ca(OH)2 ➡️ CaCl2 + 2H2O what mass of calcium hydroxide in grams is needed to produce 3.63 mol
wlad13 [49]

Answer:

2HCl (aq) + Ca

(

O

H

)

2

(aq) ---------> Ca

C

l

2

(ppt) + 2

H

2

O (aq)

let us calculate the number of moles , as per the chemical reactions;

2 moles of HCl solution reacts with one mole Calcium Hydroxide

Ca

(

O

H

)

2

One mole of HCl has mass : 36.5 g/mol, two moles of HCl will have mass, 73 g.

One mole of Ca

(

O

H

)

2

has mass 74.1 g

as per equation; 73 g of HCl reacts with 74.1 g of Ca

(

O

H

)

2

1g of HCl reacts with 74.1g / 73 of Ca

(

O

H

)

2

1g of HCl reacts with 1.015 g of Ca

(

O

H

)

2

NOW AS PER THE QUESTION MOLARITY AND VOLUME OF HYDROCHLORIC ACID IS GIVEN, IT CAN BE USED TO CALCULATE THE MASS OF HYDROCHLORIC ACID IN THE SOLUTION.

NUMBER OF MOLES of HCl ; Molarity of solution x Volume of Solution

# of moles of HCl = (0.40 mol/L ) x 350 mL

= (0.40 mol/L ) x 0.350 L = 0.14 mol

mass of HCl that makes 0.14 mol of HCl = # of moles x molar mass of HCl

mass of HCl = 0.14 mol x 36.5 g/ mol

mass of HCl = 5.11g

As per Stoichiometry , 1g of HCl reacts with 1.015 g of Ca

(

O

H

)

2

, 5.11g of HCl can react with 5.11 x 1.015 = 5.1865 g or 5.2 g of

Ca

(

O

H

)

2

.

5 0
3 years ago
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