What are the missing coefficients for the chemical equation <br> [ ] Ca + [ ] O2 → [ ] CaO

Which one of the following best represents the predicted approximate chemical shift and coupling:

mezya [45]

Answer:

C. 3.40 ppm, singlet

Explanation:

Given the information from the question .we have to select the best representation for represents the predicted approximate chemical shift and coupling for hydrogen(s). In this case, there is no neighboring hydrogen .Thus there won’t be any split .the best option answer is C. 3.40 ppm, singlet . Therefore the correct answer or option is C. 3.40 ppm, singlet.

4 0

3 years ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

50

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0

3 years ago

If a gas has a volume of 15l and a temperature of 125K, and the temperature is increased to 225K, what is the new volume

aalyn [17]

Answer:

V₂ = 27 L

Explanation:

Given data:

Initial volume = 15 L

Initial temperature = 125 K

Final temperature = 225 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 15 L × 225K / 125 k

V₂ = 3375 L.K / 125 K

V₂ = 27 L

6 0

3 years ago

1. The chemical symbol for sodium is

soldier1979 [14.2K]

Na is the symbol for sodium.

6 0

3 years ago

1. In our counting unit, an OWL is 7 items.

Marrrta [24]

Explanation:

1) If we have 1/2 OWLs of Snicker bars, then number of items or Snicker bars :

1 OWL = 7 items (given)

$\frac{1}{2}\times 7 items=3.5 items$

We have 3.5 Snickers bars.

2) If we have 100 OWLs of pencils, then number of items or pencils :

1 OWL = 7 items (given)

$100\times 7 items=700 items$

We have 700 pencils.

3) If we have 2 OWLs of iron atom, then number of iron atoms :

1 OWL = 7 items (given)

$2\times 7 items=14 atoms$ of iron

We have 14 atoms of iron.

8 0

3 years ago

What are the missing coefficients for the chemical equation [ ] Ca + [ ] O2 → [ ] CaO