Wwwwwwwwwwwwwwwwwwwwwwwweweewewwewweewweeweeweeweweweeeweew

Chemistry

1 answer:

AlekseyPX2 years ago

8 0

Explanation:

Simply multiply the # of moles of O2 by a molar ratio to give the # of moles of MgO:

#moles O2 × (2 mol MgO/1 mol O2) = # moles of MgO

where the quantity inside the parenthesis is the molar ratio between MgO and O2.

You might be interested in

Why does glutton free bread mold faster

Ann [662]

The reason is it has more sugar and energy to feed fungi, causing it to mold.

5 0

3 years ago

Read 2 more answers

What is the product(s) of the reaction below?

Lesechka [4]

Answer:

is b

Explanation:

es la b porque estpy estudiando lo mismo

7 0

2 years ago

11 Which compound has the greatest percent composition by mass of sulfur?(1) BaS (3) MgS

harina [27]

Percent composition by mass is calculated (mass of element within compound)/(mass of compound)*100. The lower the total molar mass of the compound, the greater the percent composition of sulfur. In this case, MgS would be that compound, since Mg has the lowest molar mass of the four elements bonded to S.

7 0

3 years ago

Read 2 more answers

I need help with this anyone?

valkas [14]

Just look it up on goog^le or a chart

5 0

2 years ago

Electron transfer is the term for this process. The resulting anion and cation are attracted by Coulombic forces and an ionic co

Nitella [24]

<h2>The compound formed is NaCl and $CaCl_{2}$ </h2>

Explanation:

PART 1:

Atomic number of sodium is 11.
Sodium(Na, Z = 11, Group 1A) will lose 1 electron to become $Na^{1+}$ which is isoelectronic to Neon (Ne ,Z = 10).
The symbol for the sodium ion is $Na^{+}$ .
Chlorine atom ( $Cl$ , Z = 17, Group 7A or 17) gains 1 elecron to be isoelectronic to neon.
The symbol for the compound formed is NaCl.
PART 2:
Atomic number of calcium is 20
Calcium(Ca, Z = 20 ,Group 2A) will lose two electrons to become $Ca^{2+}$ which is isoelectronic to argon.
The symbol for the ion is $Ca^{2+}.$
Two chlorine atoms (Cl, Z = 17, Group 7A or 17) each gains one electron to be isoelectronic to argon(Z = 18)
The symbol for the compound formed is $CaCl_{2}$ .

8 0

3 years ago