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ra1l [238]
3 years ago
6

The maximum kinetic energy of a box sliding from the top of a ramp to the bottom is A) at the top. B) at the bottom. C) at the e

xact middle of the ramp D) stored equally within the box at all locations.
Chemistry
2 answers:
Readme [11.4K]3 years ago
8 0

Kinetic energy of an object can be expressed in terms of its mass m and velocity v as:

KE = 1/2 * m* v²

Thus higher the velocity, greater will be the Kinetic energy. Now, as the box moves along a ramp from top to bottom, its velocity increases and so does the KE. Hence, kinetic energy is maximum at the bottom

Ans B) at the bottom


bija089 [108]3 years ago
4 0

Answer:

b

Explanation:

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Three factors that affect the solubility of a substance are pressure, the type of solvent, and volume.
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Answer: True. The three factors are as stated above

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What is the volume, in liters, of 4.00 moles of methane gas, CH4, at 13 ∘C and 1.20 atm?
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78.268L

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Which types of reactions would result in a change in temperature?
Law Incorporation [45]

Answer:

Chemical reaction involves the breaking of bonds in the reactants and formation of bonds in the products. ... If a reaction is exothermic, more energy is released when the bonds of the products are formed than it takes to break the bonds of the reactants. This is the reason for temperature change during a reaction.

Explanation:

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6 0
3 years ago
Consider the following unbalanced redox reaction:
Olegator [25]
Mn04 is being reduced
5 0
3 years ago
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

8 0
3 years ago
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