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2 years ago

I WILL GIVE YOU BRAINLIEST!!

Mathematics

1 answer:

ollegr [7]2 years ago

3 0

Answer:

32 goldfish

Step-by-step explanation:

Given:

Number of fish tanks = 8
Volume of water per fish tank = 5,544 in³
Water required by 1 goldfish = min 1,386 in³

Number of fish per tank = water per tank ÷ water per goldfish

= 5544 ÷ 1386

= 4

Therefore, each tank can hold a maximum of 4 goldfish.

Greatest number of goldfish = number of tanks × fish per tank

= 8 × 4

= 32

You might be interested in

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

7 0

2 years ago

Can someone please find the value of X for these two questions?

german

12.
50/3
14.
60/11
hope this help, if you need futher help pm me

4 0

3 years ago

The quotient of an unknown number and -13 is -14

zysi [14]

Answer:

182

Step-by-step explanation:

Quotient is division

Q/-13 = -14

Multiply each side by -13

Q/-13 * -13 = -14* -13

Q =182

The unknown number is 182

7 0

3 years ago

3/10 divided by -1/3

Snezhnost [94]

Answer:

-9/10

Step-by-step explanation:

Find the LCM of 10 and 3: 30
Alter the numerators to fit the denominators: 3 × 3 = 9, -1 × 10 = -10
Re-write the fractions: 9/30 ÷ -10/30
9/30 ÷ -10/30 = 9/30 × -30/10
9/30 × -30/10 = -270/300
$-\frac{270}{300} = -\frac{9}{10}$

I hope this helps!

8 0

3 years ago

Scores of two school basketball teams are recorded. The mean of Team A is 68. The mean of Team B is 67. What conclusion can you

Leto [7]

The conclusions that can be drawn are 3, two of a direct type and the other of an indirect type.

The direct ones are the values. Team A has an average of 68 points per game, which means that it has a good point average and, in the same way, team B, which has an average of 67, which is still a good point average per game.

The hint is the comparison of both teams, and that is that team A is one point above team B, which in terms of points per game makes them better.

5 0

2 years ago