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Y_Kistochka [10]
3 years ago
15

Please help me answer this question.

Mathematics
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

702 feet

Step-by-step explanation:

(24×27)+(9×6) = 702

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If 10x+6y=7 is a true equation, what would be the value of 6(10x+6y)?
aleksandr82 [10.1K]

Answer:

42

Step-by-step explanation:

We know that 10x + 6y = 7, and so

6(10x + 6y) = 6(7) = 42

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Why do I divid to put 16/100 in simplest form
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Find the Greatest Common Factor (GCF) of 16 and 100<span>, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 4, and get our simplified answer 4/25</span>
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Helpppp me please!!!
Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

d(x) = -\sqrt{\frac{1}{2}x+4}

d(-8) = -\sqrt{\frac{1}{2}(-8)+4}

d(-8) = -\sqrt{-4+4}

d(-8) = -\sqrt{0}

d(-8) = 0

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

f(x) = \sqrt{\frac{1}{2}x+4}

f(0) = \sqrt{\frac{1}{2}*0+4}

f(0) = \sqrt{0+4}

f(0) = \sqrt{4}

f(0) = 2

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

f(x) = \sqrt{\frac{1}{2}x+4}

f(10) = \sqrt{\frac{1}{2}*10+4}

f(10) = \sqrt{5+4}

f(10) = \sqrt{9}

f(10) = 3

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

d(x) = -\sqrt{\frac{1}{2}x+4}

d(10) = -\sqrt{\frac{1}{2}(10)+4}

d(10) = -\sqrt{5+4}

d(10) = -\sqrt{9}

d(10) = -3

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>
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