Area of the shaded region square cm
Perimeter of the shaded region cm
Solution:
Radius of the quarter of circle = 12 cm
Area of the shaded region = Area of quarter of circle – Area of the triangle
square cm.
Area of the shaded region square cm
Using Pythagoras theorem,
Taking square root on both sides of the equation, we get
cm
Perimeter of the quadrant of a circle =
cm
Perimeter of the shaded region = cm
cm
Hence area of the shaded region square cm
Perimeter of the shaded region cm
To find the y-intercept, we can convert this to slope-intercept form, or replace the value of x with 0 and solve for y.
We'll do both first.
-x + 5y = 45
5y = 45
Divide both sides by 5.
y = 9
Now let's convert it to slope-intercept.
-x + 5y = 45
Add x to both sides.
5y = 45 + x
Divide both sides by 5.
y = 1/5x + 9
y = 9
<h3><u>The y-intercept of our line is 9.</u></h3>
1. (-5,-11)
2. C, reflected across x-axis then translated.
3. A’(-1,7), B’(-4,6), C’(-2,2)
4. C’(3,-4)
5. B, rotates 90 counter clockwise and then translate
(if any of these are wrong i’m sorry! :<)
<h3>
Answer:</h3>
D. 1/24
<h3>
Step-by-step explanation:</h3>
Assuming the die is fair and the events are independent, the probability of the series of events is the product of the probabilities of the individual events.
p(even) = 3/6 = 1/2
p(odd) = 3/6 = 1/2
p(5) = 1/6
Then the joint probability is ...
.. (1/2)·(1/2)·(1/6) = 1/24
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