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2 years ago

Find the radius and the center of the circle with the given equation x^2+y^2−8x−2y=48.

Mathematics

1 answer:

Semmy [17]2 years ago

5 0

Step-by-step explanation:

x²+y²−8x−2y=48

the radius => √[(8/2)² + (2/2)² +48] =

√(16+1+48) =√65

the center => (8/2, 2/2)

=> (4, 1)

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Sylvia earns $7 per hour at her afterschool job. One week she worked several hours and received a paycheck for $91. Write and so

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91=7x
X = 13

Let x equal the amount of hours she worked at the job.

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3 years ago

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Ugo [173]

Answer:

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2 years ago

The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit

wolverine [178]

Answer:

(a) $\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

$P(t)=\frac{240t-40t^2}{t^2+20}$

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

$P(t)=\frac{240t-40t^2}{t^2+20}$ using quotient rule.

$\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}$

Simplifying

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

$P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}$

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

$P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}$

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6 0

2 years ago

Yes im playing prodigy LOL

Ilya [14]

Answer:

0,05

Step-by-step explanation:

1)First, Let’s find the mean of the data table

12 + 10 + 12 + 6 + 8 + 4 + 2 + 12 = 66

66 ÷ 8 = 8,25

2)12 - 8,25 = 3,75

10 - 8,25 = 1,25

12 - 8,25 = 3,75

6 - 8,25 = -1,75

8 - 8,25 = -0,75

4 - 8,25 = -3,75

2 - 8,25 = -5,75

12 - 8,25 = 3,75

3) 3,75 + 1,25 + 3,75 - 1,75 - 0,85 - 3,75 - 5,75 + 3,75 = 0,4

0,4 ÷ 8 = 0,05

8 0

2 years ago

Match the like terms (picture provided)

OverLord2011 [107]

-x ---------------- 1x

7y --------------- 12y

-12x^2 --------- 8x^2

a ----------------- -2a

6a^2------------ a^2

-5x^3 ---------- 15x^3

_____________________

you just have to match the terms which have the same power.

Hope it helps ^^

8 0

2 years ago