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damaskus [11]
3 years ago
5

A half-circle is joined to an equilateral triangle with side lengths of 12 units. What is the perimeter of the resulting shape?

Write your answer as a decimal rounded to the nearest tenth. Do not include the label.
Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

P = 42.84  cm

Step-by-step explanation:

A half-circle is joined to an equilateral triangle with side lengths of 12 units.

We need to find the perimeter of the resulting shape.

The perimeter of the half cirle is πr.

The diameter of the circle is 12. It means radius is 6 units.

An equilateral triangle has 3 equal sides. So, perimeter of the triangle is given by :

P = πr  + 12 +12

= 3.14(6) + 24

= 42.84  cm

Hence, the perimeter of the resulting shape is 42.84  cm.

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C.(-3, -3) and (-3,3)

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When we have a vertical line the slope is undefined.

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This has the same x values

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N+ 12 = -24<br><br> Help please
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Step-by-step explanation:

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-24 - 12 = -36

This is because whenever there are two negative signs, multiply it.

Negative x Negative = Positive

We have to do, 24 + 12 which is 36. Finally, we just put the greater number's sign to the answer. 24 is greater than 12, therefore, we put a negative sign before 36.

Hope this helps!

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3 years ago
How could you prove the product of any two negative numbers is a positive number
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7 0
4 years ago
In a survey of 468 registered voters, 152 of them wished to see Mayor Waffleskate lose her next election. The Waffleskate campai
Viefleur [7K]

Answer:

The 95% confidence interval for the proportion is (0.2824, 0.3672). The upper limit of the interval is higher than 32% = 0.32, which means that the confidence interval does not support this claim.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

n = 468, \pi = \frac{152}{468} = 0.3248

95% confidence level

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3248 - 1.96\sqrt{\frac{0.3248*0.6752}{468}} = 0.2824

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3248 + 1.96\sqrt{\frac{0.3248*0.6752}{468}} = 0.3672

The 95% confidence interval for the proportion is (0.2824, 0.3672). The upper limit of the interval is higher than 32% = 0.32, which means that the confidence interval does not support this claim.

6 0
3 years ago
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