Answer:
C(1,3) and D(1,4).
Step-by-step explanation:
The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of this quadrilateral ABCD intersect at E (2,5).
Recall that, the diagonals of a parallelogram bisects each other.
This means that; E(2,5) is the midpoint of each diagonal.
Let C and D have coordinates C(m,n) and D(s,t)
Using the midpoint rule:
The midpoint of AC is
This implies that;
The midpoint of BD is
This implies that;
Therefore the coordinates of C are (1,3) and D(1,4).