2 years ago

PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP

Mathematics

1 answer:

Nataliya [291]2 years ago

5 0

Answer:

please help me my friend

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3 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

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Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

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As, $P(z>1.28)=0.10$ [By z-table]

Then,

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So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

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3 years ago

Please help!!! if i can ill give brain thing sometimes it wont let me!!

Anika [276]

Answer:

1)24

2)15

3)5

4)48

Step-by-step explanation:

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