PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP

Mathematics

1 answer:

Nataliya [291]2 years ago

5 0

Answer:

please help me my friend

You might be interested in

A. Find and explain the error in the work shown.

Marizza181 [45]

The error is that they had placed the numbers in the wrong placeholder. Remember that the Distance formula is $D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Correct Work:

$D=\sqrt{(5-(-1))^2+(16-15)^2}\\D=\sqrt{6^2+1^2}\\D=\sqrt{36+1}\\D=\sqrt{37}\ \approx 6.08$

5 0

3 years ago

HELP What is the approximate volume of a cone with a height of 12 in. And a radius of 9in.?

Lunna [17]

$SURFACE \: \: AREA \: \: AND \: \: VOLUMES \\ \\ \\\\Volume \: \: of \: \: cone \: \: = \: \: \frac{1}{3} \pi {r}^{2} h \\ \\ \\ We \: are \: given \: that \: \: - \: \: \: \\ \: \: \\ \: Radius \: = \: 9 \: \: in. \\ \\ \: Height \: = \: 12 \: \: in. \\ \\ \: \: \: \pi \: = \: 3.14 \\ \\ Volume \: \:of \: \: Cone \: \: = \: \: \frac{1}{3} \times 3.14 \times 9 \times 9 \times 12 \\ \\ \\ Volume \: \: of \: \: Cone \: \: = \: \: 1017.36 \: {in.}^{3}$