Answer: The mean of the data is 433.75, variance of the data is 99667.19 and the standard deviation of the data is 315.7011.
Explanation:
The given data is 900, 35, 500 and 300.
The number of observation is 4.
Formula of mean is,
The formula of variance is given below,
The variance of the data is 99667.19
The standard deviation of the data is 315.7011.
The other information or values of given chart is shown in the attached table.
The slope is 3/1
hope this helps
Answer: =2084
4+2(82)(42)+6+4+6+6+6+2+2
=4+264(42)+6+4+6+6+6+2+2
=4+2(64)(16)+6+4+6+6+6+2+2
=4+(2)(1024)+6+4+6+6+6+2+2
=4+2048+6+4+6+6+6+2+2
=2052+6+4+6+6+6+2+2
=2058+4+6+6+6+2+2
=2062+6+6+6+2+2
=2068+6+6+2+2
=2074+6+2+2
=2080+2+2
=2082+2
=2084
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
49/6 into a mixed number would be 8 1/6. This is because you would see how many times 6 can go into 49. Since 6 times 8= 48, you subtract that from 49. You are left with one. You put the number you multiplied 6 by as the whole number and the leftover one over six. I hope this helps!
