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motikmotik
3 years ago
15

Find the slope of this line

Mathematics
2 answers:
asambeis [7]3 years ago
6 0

Answer:

5/2

Step-by-step explanation:

Illusion [34]3 years ago
6 0

Answer:

(2, 0) and (4, 6)

6 - 0          6

_____ = ____ = 3, 6/2 or 3 is your answer

4 - 2           2

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telo118 [61]
2 x 2 x 6 = 24ft²
1 x 2 x 12 = 24ft²
4 0
3 years ago
The volleyball team sold 16 items on the first day of a bake sale, 28 items on the second day, and 12 items on the last day. The
valina [46]
60 items were for sale because you need to add together the amounts that were sold plus what was left over, giving you everything that they had for sale.
6 0
3 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
In august the simons water bill was $48.in September it was 15% lower . What was the simons water bill in September
slega [8]
Water bill of Simons in the month of August = $48
Percentage of bill that was lower in the month of September = 15%
then
Amount of bill that was lower in the month of September = (15/100) * 48
                                                                                           = 720/100 dollars
                                                                                           = 7.2 dollars
So
The bill for the month of September = (48 - 7.2) dollars
                                                          = 40.8 dollars
So Simon will have to pay $40.8 as the water bill for the month of September. I hope the procedure is clear enough for you to understand.
3 0
3 years ago
Read 2 more answers
2. Every month, Jenny and Gopal ________ the orphanages in China. They have been to five orphanages so far.
aleksandr82 [10.1K]

Answer:

2. A

3. B

4. B

5. B

6. C

7. C

8. B

9. D

10. C

6 0
3 years ago
Read 2 more answers
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