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irina [24]
3 years ago
6

-7x - 3= 2 - 7x - 5 Step by step

Mathematics
1 answer:
Romashka [77]3 years ago
5 0
Combine like terms first
-7x-7x=2-3-5
-14x=-6
Divide by -14 on both sides
X=-6/-14
X=-3/7
Hopefully this helps also I’m working on this aswell so pardon me if I’m wrong
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Which step shows the result of applying the subtraction property of equality? 1/4 (12x+8)+4=3
frosja888 [35]

Answer:

Those steps shows the result of applying the subtraction property of equality, In which an integer value is subtracted from both the sides. Step 3 show the subtraction property of equality.

Step-by-step explanation:

The given expression is

\frac{1}{4}(12x+8)+4=3

Step 1: Use Distributive property

          \frac{1}{4}(12x)+\frac{1}{4}(8)+4=3

         3x+2+4=3

Step 2: Add like terms.

          3x+6=3

Step 3: Subtract 6 from both sides

           3x+6-6=3-6           (Subtraction property of equality)

           3x=-3

Step 4: Divide both sides by 3.

            x=-1

Therefore those steps shows the result of applying the subtraction property of equality, In which an integer value is subtracted from both the sides.

3 0
3 years ago
Read 2 more answers
Help on #1,2,3 please don't understand help me. Thanks Happy New Year!
s344n2d4d5 [400]
So #2 is 2 students and #3 is 3/6
hope that help
8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP<br> BRAINLIEST
Vedmedyk [2.9K]

Answer:

12

is the anser

Step-by-step explanation:

4 0
3 years ago
The standard form of (6x1)+ 1000/8 =
Maslowich

Answer:

131

Step-by-step explanation:

Hope this helps! Have a great day ahead :)

4 0
3 years ago
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A simple random sample (SRS) of 150 is taken from a population with a 0.6 proportion of success. An independent SRS of 250 is ta
Virty [35]

Answer:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

Step-by-step explanation:

For this case we have the following data:

n_1 =150 represent the random sample 1 selected

\hat p_1 =0.6 represent the proportion of success for the sample 1 selected

n_2 =250 represent the random sample 2 selected

\hat p_2 =0.3 represent the proportion of success for the sample 2 selected

We know for this case that we can use the normal approximation since for both cases we have:

n_1 p_1  =90 \geq 10, n_1 (1-p_1)=60 \geq 10

n_2 p_2  =75 \geq 10, n_2 (1-p_2)=175 \geq 10

We have the randomization condition and we assume that the two samples are <10% of the entire population size.

So then we can use the following distribution for the proportions:

p \sim N( \hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

For this case we want to find the distribution for the difference of these two proportions and we have this:

p_1 -p_2 \sim N (\hat p_1 -\hat p_2 , \sqrt{\frac{\hat p_1 (1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}})

So then the dtandard deviation would be given by:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

4 0
4 years ago
Read 2 more answers
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