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Illusion [34]
3 years ago
15

The jailbreak property that, if the user turns the device off and back on, the device will start up completely, and the kernel w

ill be patched without the help of a computer - in other words, it will be jailbroken after each reboot - comes under which type?
Computers and Technology
1 answer:
Natali5045456 [20]3 years ago
3 0

Answer: An untethered jailbreak.

Explanation:

Jailbreaking is the process of installing a modified set of kernel patches that in turn enables users to run third-party applications not endorsed by the Operating System vendor. It is the sytem of bypassing user bridges as set by Apple, such as modifying the OS, having admin privileges, and ability to install unofficially applications that are approved by "side loading."

There are different types of jailbreak. An untethered jailbreak uses mechanisms that are extremely strong enough to allow the user to turn their device off and on at will, with the device starting up completely, & the kernel will be patched but without the help of a computer which means it will be jailbroken even after each reboot.

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Write a program that first gets a list of integers from input. Then, get another value from the input, and output all integers l
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Answer:

The c++ program for the given scenario is given below.

#include <iostream>

using namespace std;

int main() {

   int len=20, arr[len], data;    

   // initialize all elements of the array to 0

   for(int i=0; i<len; i++)

   {

       arr[i] = 0;

   }    

   cout<<"This program outputs all the numbers less than or equal to the given number."<<endl;

   cout<<"Enter the list of numbers. Enter 0 to stop entering the numbers. "<<endl;

   for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       // 0 indicates user wishes to stop entering values  

       if(arr[i] == 0)

           break;

       else

           continue;

   }    

   // number from which the list is to be compared

   cout<<"Enter the number to be compared."<<endl;

   cin>>data;

     

   cout<<"The values less than or equal to the number "<<data<<" are "<<endl;

   for(int i=0; i<len; i++)

   {  

       // 0 indicates the end of the list entered by the user

       if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }    

   return 0;    

}  

OUTPUT

This program outputs all the numbers less than or equal to the given number.

Enter the list of numbers. Enter 0 to stop entering the numbers.  

23

45

67

89

10

0

Enter the number to be compared.

59

The values less than or equal to the number 59 are  

23

45

10

Explanation:

This program takes input only from the user and makes no assumptions.

The list of numbers entered by the user are stored in an array. If the user input is less than the size of the array, the remaining elements are set to 0.

While taking input from the user, if any element of the array is found to be 0, the loop is discontinued.

for(int i=0; i<len; i++)

   {

       cin>>arr[i];        

       if(arr[i] == 0)

           break;

       else

           continue;

   }  

Same test is applied when all the numbers less than the given number are displayed.

for(int i=0; i<len; i++)

   {  

        if(arr[i]==0)

           break;

       if(arr[i] <= data)

           cout<<arr[i]<<endl;

   }

The above program takes into account all the specifications in the given question.

5 0
3 years ago
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