The mathematics department sponsors Math Family Fun Night every year. In year 1, there were 35 participants. In year 3, there we
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If $11,000 is invested, $33,000 is the value of the investment at the end of 25 years if the interest is 8% simple interest and $75,333.23 is the value of the investment at the end of 25 years if the interest is 8% compounded annually. This can be obtained by using formulas for simple interest and compound interest.
<h3>What is the formulas of simple interest and compound interest?</h3>- Simple interest
A = P(1 +Rt/100) , P = principle amount ,R = rate of interest, t = time(in years)
- Compound interest (annually)
A = P(1 + R/100)^t , P = principal amount, R = rate of interest, t = time(in years)
<h3>What is the value of investment?</h3>
Given that,
P = $11,000 , R = 8%, t = 25 years
- 8% simple interest
A = P(1 +Rt/100) = = $33,000
- 8% compounded annually
A = P(1 + R/100)^t = =
= $75,333.23
Hence If $11,000 is invested, $33,000 is the value of the investment at the end of 25 years if the interest is 8% simple interest and $75,333.23 is the value of the investment at the end of 25 years if the interest is 8% compounded annually.
Learn more about simple interest and compound interest:
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: If $11,000 is invested in an account for 25 years. Find the value of the investment at the end of 25 years if the interest is:
(a) 8% simple interest
(b) 8% compounded annually
Step 1:
Start by putting
in front of each term
![\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5By%20cos%20x%5D%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B5x%5E2%5D%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%203y%5E2%5D)
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Step 2:
Deal with the terms in 'x' and the constant terms
![\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bycosx%5D%3D%2010x%2B%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5B3y%5E2%5D%20%20)
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Step 3:
Use the chain rule for the terms in 'y'
![\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bycosx%5D%3D10x%2B6y%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%20)
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Step 4:
Use the product rule on the term in 'x' and 'y'
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Step 5:
Rearrange to make
the subject
![[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)](https://tex.z-dn.net/?f=%5Bcos%28x%29%20-%206y%5D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%3D10x%20%2B%20y%20sin%28y%29%20)
⇒ Final Answer
Start by putting
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Step 2:
Deal with the terms in 'x' and the constant terms
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Step 3:
Use the chain rule for the terms in 'y'
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Step 4:
Use the product rule on the term in 'x' and 'y'
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Step 5:
Rearrange to make