Question

100 points & will give brainliest!

Answer 1

$\\ \sf\longmapsto \left\{x|3$

The solution is

$\\ \sf\longmapsto (3,4)\cup (4,13)$

Now Find all elements

$\\ \sf\longmapsto \left\{5,6,7,8,9,10,11,12\right\}$

Answer 2

Answer:

$\displaystyle (3, 4) \cup (4, 13)$

Step-by-step explanation:

We are given the set:

$\displaystyle \left\{ x| 3 < x < 13 \text{ and } x \neq 4\right\}$

And we want to express this in interval notation.

In words, this reads: all values of x between 3 and 13 and x does not equal 4.

Hence:

$\displaystyle (3, 4) \cup (4, 13)$

We use parentheses as we do not include the values of 3 and 13 inside our interval. Likewise, since x cannot equal 4, we skip four, but use the union symbol to connect the two intervals.