All categories

3 years ago

100% is 75 oranges what percent is 250 oranges?

Mathematics

1 answer:

Whitepunk [10]3 years ago

4 0

Answer:

x=333.33%

Step-by-step explanation:

hello

you can resolve this by using the rule of 3,let´s see

75 oranges =100%

250 oranges = x%?

75 oranges* x%=250 oranges *100%

$x=\frac{250*100}{75}$

x=333.33%

Have a great day.

You might be interested in

Subtract: (x^2 - 8x + 5)-(-3x^2 + 5x-9)

Marianna [84]

Answer: 4x^2 -13x + 14

Step-by-step explanation:

(x^2 - 8x + 5)-(-3x^2 + 5x-9)

Subtract -3x^2 from x^2

(4x^2 - 8x + 5)-(5x-9)

Subtract 5x from -8x

(4x^2 -13x + 5)-(-9)

Subtract 9 from 5

4x^2 -13x + 14

7 0

3 years ago

Plzzz help i am ineeeddeddeedeededed of it!!!

Vikentia [17]

Sallys statement is always true
for example:
-6 + 2 = -4
but if I turn it around
2 - 6 = -4
same answer

-6 -6 = -12
swap around -6 - 6 = 12
same answer

again -3 + 6 = 3
and 6 - 3 = 3

6 0

3 years ago

The velocity v and maximum height h of the water being pumped into the air are related by the equation v=\sqrt(2gh) where g is t

Whitepunk [10]

The velocity v and maximum height h of the water being pumped into the air are related by the equation

v= $\sqrt{2gh}$

where g = 32

(a) To find the equation that will give the maximum height of the water , solve the equation for h

v= $\sqrt{2gh}$

Take square root on both sides

$v^2$ = 2gh

Divide by 2g on both sides

$\frac{v^2}{2g}$ = h

So maximum height of the water h = $\frac{v^2}{2g}$

(b) Maximum height h= 80

velocity v= 75 ft/sec

Given g = 32

h = $\frac{v^2}{2g}$

h = $\frac{75^2}{2*32}$

h= 87.89 ft

The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.

So the pump will meet the fire department needs.

8 0

3 years ago

The math problem is 100 x 0.496

Setler79 [48]

Answer:

49.6

Step-by-step explanation:

To multiply a power of (ten) 10 by a decimal all you have to do is move the decimal point the number of zeros (0) in the power of 1 to the right.

So to do this equation you move the decimal point in 0.496 you move the decimal point two (2) times to the right to get 49.6.

3 0

2 years ago

Read 2 more answers

Using the provided measures determine the measure of angle K.

forsale [732]

Answer:

B. 34.90°

Step-by-step explanation:

✔️First, find GF using Trigonometric function:

Reference angle = 58°

Adjacent length = GF

Hypotenuse = 6 cm

Apply CAH, thus:

Cos 58 = Adj/Hyp

Cos 58 = GF/6

GF = 6*Cos 58

GF = 3.17951558 ≈ 3.18 cm

✔️Find angle K using the Sine Rule:

$\frac{sin(K)}{GF} = \frac{sin(G)}{KF}$

Substitute

$\frac{sin(K)}{3.18} = \frac{sin(64)}{5}$

Multiply both sides by 3.18

$sin(K) = \frac{sin(64)}{5}*3.18$

$sin(K) = 0.5716$

$K = sin^{-1}(0.5716)$

K = 34.8618741° ≈ 34.90°

5 0

2 years ago