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love history [14]
3 years ago
12

The cable company is analyzing data from two satellite television providers to determine whether their users spend more time wat

ching live television or shows that have been recorded. Satellite Company X : 89 live, 430 recorded Satellite Company Y : 65 live, 94 recorded What is the probability that a randomly selected customer from Company Y watches recorded shows more often than live television? Give your answer in percent form rounded to the nearest whole percent.
Mathematics
2 answers:
Phoenix [80]3 years ago
3 0

Answer:

59%

Step-by-step explanation:

The information from Satellite Company Y is:

65 people watch live and 94 people watch recorded.

The total number of people from Y is:

65 + 94 = 159

So the probability that a random person from Y watches recorded shows more often is given by the division of the number of people watching more recorded shows (94) over the total number of people (159):

Probability = 94 / 159 = 0.5912 = 59.12%

Rounding to nearest whole percent, we have 59%

gregori [183]3 years ago
3 0

Answer:

59%

Step-by-step explanation:

I got 100%

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It is known that the life of a particular auto transmission follows a normal distribution with mean 72,000 miles and standard de
scoray [572]

Answer:

a) P(X

P(z

b) P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

P(z>-0.583)=1-P(Z

c) P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

d) z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the life of a particular auto transmission of a population, and for this case we know the distribution for X is given by:

X \sim N(72000,12000)  

Where \mu=72000 and \sigma=12000

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using excel or the normal standard table and we got:

P(z

Part b

P(X>65000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>65000)=P(\frac{X-\mu}{\sigma}>\frac{65000-\mu}{\sigma})=P(Z>\frac{65000-72000}{12000})=P(z>-0.583)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>-0.583)=1-P(Z

Part c

P(X>100000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>100000)=P(\frac{X-\mu}{\sigma}>\frac{100000-\mu}{\sigma})=P(Z>\frac{100000-72000}{12000})=P(z>2.33)

And we can find this probability using the complement rule and excel or the normal standard table and we got:

P(z>2.33)=1-P(Z

Sicne this probability just represent 1% of the data we can consider this value as unusual.

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=72000 +1.28*12000=87360

So the value of height that separates the bottom 90% of data from the top 10% is 87360.  

5 0
3 years ago
In triangle RST, angle R is a right angle. If TR = 6 and TS = 8, what is the length of RS
lisabon 2012 [21]

Answer:

RS = 2\sqrt{7}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

RS² + RT² = TS² , that is

RS² + 6² = 8²

RS² + 36 = 64 ( subtract 36 from both sides )

RS² = 28 ( take the square root of both sides )

RS = \sqrt{28} = \sqrt{4(7)} = 2\sqrt{7} ≈ 5.3 ( to 1 dec. place )

8 0
3 years ago
The ratio of your monthly allowance compared to your friends monthly allowance is five to three and totally you and your friend
bonufazy [111]
15$ is the answer to this question.
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In circle F with m∠EFG=54m∠EFG=54 and EF=19
elena-14-01-66 [18.8K]

Answer:

17.907082 unit

Step-by-step explanation:

According to the Question,

Given, A circle with centre F, ∠EFG=54 and EF=19 .

length of arc EG = Radius(EF) × ∠EFG(in Radian)

  • We Know, 1 degree = 0.0174533 Radian
  • 54 degree = 0.942478 Radian

length of arc EG = 19 x 0.942478 ⇔ 17.907082 unit

(For Diagram please find in attachment)

3 0
3 years ago
2(4x - 12) + 3x = 6x + 1<br><br> help!! ahh
Anuta_ua [19.1K]
<span>2(4x - 12) + 3x = 6x + 1

Distribute.

8x - 24 + 3x = 6x + 1

Combine like terms.

11x - 24 = 6x + 1

5x = 25

x = 5

</span>
8 0
3 years ago
Read 2 more answers
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