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uranmaximum [27]
3 years ago
5

Qu. In a triangle ABC, side AB has length 10cm, side AC has length 5cm, and angle BAC = θ

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

To find cosθ, use the formula for the area of a triangle i.e. AREA=1/2 x a x b x sinC.=> For this case: 15= 1/2 x 10 x 5 x sinC to find sinC.=> SinC = 3/5 thus, Arcsin(3/5)=+- 4/5 or +-0.8

To find the exact length of BC, use the cosine rule.=> c(sq)=a(sq)+b(sq)-2abCosC=> c(sq)=10(sq)+5(sq)-2(10)(5)(+-4/5)=> c(sq)= Square root of 205

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A Traveller changed EC $1800 to Barbados currency. Calculate the amount received
natta225 [31]

Answer:

1350 bajan dollar

Step-by-step explanation:

The exchange rate of EC dollar to Barbados currency is

1 EC dollar = 0.75 Barbados currency

EC $1800 in Barbados currency = EC $1800 x 0.75 = 1350 bajan dollar

8 0
3 years ago
Please help! Thanks thO!
Snezhnost [94]

Answer:

8

Step-by-step explanation:

The sum of two interior angles in a triangle is equal to an exterior angle

7x - 4 + 9x + 4 = 128° add like terms

16x = 128 divide both sides by 16

x = 8

7 0
4 years ago
Yes or no?
timofeeve [1]

1). Sometimes.
2). Always.
3). Sometimes.
4). Sometimes.
5). Always.
6). Always.


8 0
3 years ago
A certain railway company claims that its trains run late 5 minutes on the average. The actual times (minutes) that 10 randomly
iragen [17]

Answer:

Option C)  We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 5 minutes

Sample mean, \bar{x} = 9.130 minutes

Sample size, n = 10

Alpha, α = 0.01

Sample standard deviation, s = 1.4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 5\text{ minutes}\\H_A: \mu \neq 5\text{ minutes}

We have to construct 99% confidence interval.

99% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.01} = \pm 3.249  

9.130 \pm 3.249(\dfrac{1.4}{\sqrt{10}} ) = 9.130 \pm 1.4383 = (7.6917,10.5683)

99% Confidence interval:  (7.6917,10.5683)

Since the population mean does not lie in he calculated confidence interval, thus, we fail to accept the null hypothesis and accept the alternate hypothesis.

Option C) We would reject the claim that the trains run late an average of 5 minutes and conclude that they run late an average of more than 5 minutes since the 99% confidence interval exceeds 5.

6 0
4 years ago
Use simple interest to find the ending balance. $215 at 8% for 8 years
ira [324]

Answer:

$ 352.6

Step-by-step explanation:

SI = P (1 + rt)

= 215 [ 1 + (0.08) x 8]

= 215 (1 + 0.64)

= 215 (1.64)

= $ 352.6

3 0
3 years ago
Read 2 more answers
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