If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.
Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)
We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.
First option is set of rational numbers which is right for the function.
Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.
Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.
Hence the domain is set of rational numbers.
Now we will solve the second part of the question
f(x)=3x+8(3-x)
we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.
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Answer:
Step-by-step explanation:
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The answer may or may not be B
Answer:
x = 15
Step-by-step explanation:
Consider the right triangle on the left with hypotenuse h₁ , then
Using Pythagoras' identity
h₁² = x² + 9²
Consider the right triangle on the right with hypotenuse h₂ , then
h₂² = x² + 25²
Now consider the large right triangle with legs h₁ and h₂ , then
h₁² + h₂² = (9 + 25)² , substitute values
x² + 9² + x² + 25² = 34² , that is
2x² + 81 + 625 = 1156
2x² + 706 = 1156 ( subtract 706 from both sides )
2x² = 450 ( divide both sides by 2 )
x² = 225 ( take the square root of both sides )
x = 
= 15
