3 years ago

Pls answer will choose brainliest

Mathematics

1 answer:

MrRissso [65]3 years ago

4 0

Hi ;-)

$\text{x}=-1 \ \text{and} \ \text{y}=-4\\\\\dfrac{5x^2-y^2+3}{2x-4y}=\dfrac{5\cdot(-1)^2-(-4)^2+3}{2\cdot(-1)-4\cdot(-4)}=\dfrac{5\cdot1-16+3}{-2+16}=\boxed{-\frac{8}{14}}$

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