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2 years ago

Find the lest number which is exactly divisible by 36 & 90 Maths

Mathematics

2 answers:

Marrrta [24]2 years ago

5 0

To find the least number,

Which is exactly divisible by 36 and 90. We have to find the HCF of 36 and 90.

→ 36 = 2 × 2 × 3 × 3

→ 90 = 2 × 3 × 3 × 5

Then the required HCF will be,

→ 2 × 2 × 3 × 3 × 5

→ 180 (HCF)

Thus, 180 is the least number which is exactly divisible by 36 and 90.

prisoha [69]2 years ago

3 0

Answer:

Step-by-step explanation:

You need to find the HCF of 36 and 90.

Prime factors of each:

36 = 2*2*3*3
90 = 2*3*3*5

HCF includes all prime factors of both numbers:

HCF(36, 90) = 2*2*3*3*5 = 180

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