Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:
3
Step-by-step explanation:
The computation of the mean is shown below:
= Total sum ÷ number of observations
= (1 + 2 + 2 + 2 + 3 + 1 + 4 + 0 + 5 + 3 + 6 + 2) ÷ 12
= 31 ÷ 12
= 2.58
= 2.6
= 3
Answer:
She can only make 5/6 of her recipe with the amount of milk that she has.
Step-by-step explanation:
Some data of this problem is missing, the data missing is:
Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.
Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:
÷
When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:
÷
×
If we simplify this last expression we have:

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.
<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>
Uh i think it’s uhh.... i think it’s a carrot
The correct answer is b) 2