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vlabodo [156]
3 years ago
15

Find the value of x 50 x

Mathematics
1 answer:
finlep [7]3 years ago
6 0
The value of X is 80
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Write each statement as a decimal to two decimal places. $6.00 to 95 cents = 3 hours to 35 minutes = 42 inches to 2 feet = (Hint
Kruka [31]

Answer/Step-by-step Explanation:

The above given statements can be written as decimals by first writing both quantities in a statement in the same unit.

1. $6.00 to 95 cents:

This is same as $6.00 : 95 cents = \frac{6.00}{95}

Convert $6 .00 to cents to make both quantities be in the same unit.

$1 = 100 cents

$6.00 = 6*100 = 600 cents

\frac{600}{95} = 6.32 (to 2 d.p)

2. 3 hours to 35 minutes:

Convert 3 hours to 35 mins

1 hr = 60 mins

3 hrs = 3*60 = 180 mins

180mins : 35 mins = \frac{180}{35} = 5.14 (2 d.p)

3. 42 inches to 2 feet:

Convert 2 ft to inches

1 ft = 12 inches

2ft = 2*12 = 24 inches

42 in:24 in = \frac{42}{24} = 1.75

8 0
3 years ago
Please help me I don't understand
kompoz [17]

x intercept (-1, 0)

y intercept (0, -3)

The 4th option

Coordinates are always written like (x,y) And the x-intercept always has a y coordinate of 0, while the y-intercept always has a x coordinate of 0.

3 0
3 years ago
The cost of a cd is $18.95 makeup is 70%
kykrilka [37]
$5.69 Discount $13.27
8 0
4 years ago
A new car was put into production. It involved many assembly tasks. Each car was inspected at the end of the assembly line and t
allsm [11]

Answer:

About 300 of every 1,000 cars assembled should have one or more defects

Step-by-step explanation:

From the sample of 100 cars, we can estimate the total number of defective cars, using a rule of three.

In this question:

For each 100 cars, 30 defective.

How many defective for 1000?

100 cars - 30 defective

1000 cars - x defective

100x = 30*1000

Simplifying by 100

x = 30*10

x = 300

About 300 of every 1,000 cars assembled should have one or more defects

5 0
3 years ago
Graph the following equation <br> y = 2/3x
Oxana [17]

Any equation in the form

y=mx

Is a line. So, we only need to sample two points, and then connect them.

If we choose, for example, x=0 and x=3, we have

x=0\implies y=\dfrac{2}{3}\cdot 0 = 0,\quad x=3\implies y=\dfrac{2}{3}\cdot 3 = 2

So, when x=0 then y=0, i.e. the line passes through the origin (0,0).

Similarly, when x=3 then y=2, i.e. the line passes through the point (3,2).

Connect these two points and you have the line.

7 0
4 years ago
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