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3 years ago

15

Find the value of x 50 x

1 answer:

finlep [7]3 years ago

6 0

The value of X is 80

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In parallelogram HJKL if m∡HJK=110∘ find m∡JKL.

pav-90 [236]

Answer:

∠ JKL = 70°

Step-by-step explanation:

Consecutive angles in a parallelogram are supplementary , then

∠ JKL + ∠ HJK = 180°

∠ JKL + 110° = 180° ( subtract 110° from both sides )

∠ JKL = 70°

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3 years ago

When is 'L' larger than 'XL'?

Genrish500 [490]

Recall that the roman numeral "L" has a value of 50. Meanwhile, the value of "XL" is L - X = 50 - 10 = 40. Comparing their numerical values, we have 50 > 40 or L > XL. This means that in Roman numeral, we find that L is actually larger than XL. Thus, the answer is<span> in Roman Numerals.</span>

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4 years ago

Which number is an irrational number

mixer [17]

The square root of 11 since it can’t be solved repeating the same every time like the others! Hope this helps ☺️

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3 years ago

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Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

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3 years ago

Write an<br> explicit formula for an, the nth term of the sequence 2, -1, –4, ....

Agata [3.3K]

Answer:

a(n) = a(1) -3(n-1)

Step-by-step explanation:

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3 years ago

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