Answer:
I think you will need 3 cups
X^2(x+4) x 3x^2(x-1)
(X^3+4x^2) x (3x^3 -3x^2)
3x^6 -3x^5+12x^5 -12x^4
3x^6 +9x^5-12x^4
I think that’s how you do it
Answer:
and ![54/18 = 3](https://tex.z-dn.net/?f=54%2F18%20%3D%203)
Step-by-step explanation:
Given
![Sections = 3](https://tex.z-dn.net/?f=Sections%20%3D%203)
per section
![Total\ Measurement=54](https://tex.z-dn.net/?f=Total%5C%20Measurement%3D54)
Required
Model the scenario
The model of this scenario is:
![Sections * Measurement = Total\ Measurements](https://tex.z-dn.net/?f=Sections%20%2A%20Measurement%20%3D%20Total%5C%20Measurements)
This gives:
<em />
<em> -- This represents the multiplication model</em>
Divide both sides by 18
![3 * 18/18 = 54/18](https://tex.z-dn.net/?f=3%20%2A%2018%2F18%20%3D%2054%2F18)
![3 * 1 = 54/18](https://tex.z-dn.net/?f=3%20%2A%201%20%3D%2054%2F18)
![3 = 54/18](https://tex.z-dn.net/?f=3%20%3D%2054%2F18)
Reorder
<em />
<em> -- This represents the division model</em>
Answer:
at the answer is about 5.29
Step-by-step explanation:
to do this u need the pythagorean theorem.
a squared+ b squared=c squared
we have the a and c values so what u would do is c squared- a squared. (8 squared - 6 squared = b squared.