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3 years ago

Simplify 4n5 + 3.5n5 + (-2.1n5). 4.4 n5 5.4 n5 20 n5 6.4 n5

Mathematics

1 answer:

ella [17]3 years ago

7 0

Answer:

$4 {n}^{5} + 3.5 {n}^{5} + ( - 2.1 {n}^{5} )$

first create a bracket:

$= ( {4n}^{5} + 3.5 {n}^{5} ) + ( - 2.1 {n}^{5} )$

then solve the first bracket:

$= {7.5 {n}^{5} } + ( - 2.1 {n}^{5} )$

then open the remaining bracket:

$= {7.5n}^{5} - {2.1n}^{5}$

carryout the subtraction operation:

$= (7.5 - 2.1) {n}^{5} \\ { \boxed{ = {5.4n}^{5} }}$

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56 = 17n - 29<br> what is the value of n

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Answer:

n=5

Step-by-step explanation:

take 29 add to 56 then divided by 17

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3 years ago

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Which statement is true when all points of a line lie in a plane?

stira [4]

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3 years ago

A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find

Shkiper50 [21]

Answer:

Therefore the probability that the marble is blue or even numbered is $\frac{11}{15}$

Step-by-step explanation:

Probability: The ratio of favorable outcomes to the total outcomes.

It is denoted by P.

$Probability= \frac{\textrm{favorable outcomes}}{\textrm{Total outcomes}}$

Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)

$=\frac{\textrm{Total number of blue marbles}}{\textrm{Total number of blue marbles}}$

$=\frac{7}{15}$

The probability of getting a even marble is P(B)

$=\frac{\textrm{The number of even number marbles}}{\textrm{Total number of marbles}}$

$=\frac{7}{15}$

The probability of getting a even numbered blue marble P(A∩B)

$=\frac{3}{16}$

P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)

$=\frac{7}{15} +\frac{7}{15}-\frac{3}{15}$

$=\frac{11}{15}$

Therefore the probability that the marble is blue or even numbered is $\frac{11}{15}$

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4 years ago

Relate ratios in right triangles

SIZIF [17.4K]

Answer:

Step-by-step explanation:

Cos is the adjacent side over the hypotenuse. The adjacent side to <E is side ED. The hypotenuse is side EF. ED/EF. They do not go right out and give you this choice, but you see that B says the same thing.

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2 years ago

I need help with this question in my math homework

Yakvenalex [24]

Answer:

∠CDE ↔ 50°
∠FEG ↔ 75°
∠ACB ↔ 55°

Step-by-step explanation:

To solve angle problems like this, you make use of three relations:

linear angles have a sum of 180°
angles in a triangle have a sum of 180°
vertical angles have the same measure

The attached diagram shows the measures of all of the angles of interest in the figure. The ones shown in blue are the ones that have the measures and names on the list of answer choices.

A good place to start is with the linear angle pair at A. Since the sum of the two angles is 180°, the angle at A that is inside the triangle will be ...

180° -130° = 50°

Then the missing angle in that triangle at C will have the measure that makes the sum of triangle angles be 180°:

∠ACB = 180° -50° -75° = 55° . . . . . this is one of the angles on your list

Similarly, the angle at E inside triangle FEG will have a measure that makes those angles have a sum of 180°:

∠FEG = 180° -60° -45° = 75° . . . . . this is one of the angles on your list

The two angles whose measures we just found are vertical angles with the base angles in triangle CDE, so that triangle's angle D will have a measure that makes the total be 180°.

∠CDE = 180° -55° -75° = 50° . . . . . this is one of the angles on your list

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3 years ago