1/5^2 = 1/25
1/5^1 = 1/5
1/5^0 = 1
1/5^-1 = 5
1/5^-2 = 25
Answer:
<h2>3. Infinitely many</h2>
Step-by-step explanation:



[(x**-2) y**2 .z)**2]**2 (x**-8)(y**8)(z**4)
----------------------- = -----------------------------
[x**2 . y**3]**2 (x**4) (y**6)
(y**8)(z**4) (y**2)*(z**4)
--------------------- = -------------
(x**12) (y**6) (x**12)
Answer:
I believe it would be A hope this helps!
Step-by-step explanation: