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Alona [7]
3 years ago
14

The crew on fishing boat caught four fish weighing a total of 1092 pounds. The tarpon weighed twice as much as the amberjack and

the white marlin weighed twice as much as the the tarpon. The weight of the tuna was 5 times the weight the amberjack. How much did each fish weigh?
Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
X= weight of amberjack
2x= weight of tarpon
4x= weight of marlin
5x= weight of tuna

x + 2x + 4x + 5x= 1092
12x=1092
x= 91

Amberjack weighs 91 pounds
Tarpon= 2 x 91 = 182 pounds
Marlin= 4 x 91= 364 pounds
Tuna = 5 x 91 = 455 pounds
allsm [11]3 years ago
4 0
Ta = tarpon
am = amberjack
wm = white marlin
tu = tuna

ta + am + wm + tu = 1092
ta = 2 * am
wm = 2 * ta = 4 * am
tu = 5 * am

2 * am + 4 * am + 5 * am + am = 12 am = 1092
am = 91
ta = 2 * 91 = 182

etc...
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Question 1:

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The picture shown splits the image into 2 half circles and two triangles. When finding the area, you can look at the two halves as one whole. The area of a circle is calculated by putting the radius to the power of two and multiplying by pi. The picture gives you the diameter, which is 5 feet. The diameter of a circle is twice the radius, so divide 5 by 2, square that number, and multiply by pi to find the area of one whole circle:

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Now we need to find the area of the two triangles. Like the circles, these two triangles make up one whole triangle. The base of the triangle is given: 6 feet. The height of this triangle is also given as 4 feet. The formula for the area of a triangle is base*height/2, so multiply 4 by 6 and divide by 2:

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To find the perimeter, we need to look at the problem similarly. The perimeter can be thought of as the length around a figure. The formula for the perimeter of a circle, called the circumference, is diameter*pi, so multiply the diameter, 5, by pi to find the distance around the rounded parts of the figure

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This figure is made up of two shapes: A square, and a semicircle, or half circle. Since it is half of a circle, we need to calculate the area of a circle, and divide by two. The problem gives us a diameter of 6, which we know we must divide by two because a diameter is twice the size of the radius, and the formula is radius^2*pi. Divide 6 by 2:

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