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3 years ago

Pls This The Last One I Need Help On

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

the shape move to the side it flips then it goes down and finally it turns again.

Step-by-step explanation:

daser333 [38]3 years ago

3 0

Answer:

From 4-5 the shape is rotated 180 degrees.

Step-by-step explanation:

If you are standing up and you jump to face the other way your turning 180 degrees. If you turn to your side that would be 90 degrees and for a full turn 360 degrees.

Hope this helps, please leave any questions or concerns in the comments. Thanks

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Bottles of sparkling water usually cost $1.69 each. This week they are in sale for 4 for $5. You bought one last week and one th

Phantasy [73]

Answer:

The cost of 1 sparkling bottle in this week is less than last week, so we pay less this week.

We pay $0.44 less this week.

Step-by-step explanation:

Given,

Cost of 1 sparkling bottle last week = $1.69

This week cost of 4 bottles is $5.

So we have to find the cost of 1 bottle.

For this we use the unitary method, we get the cost of 1 bottle;

Cost of 1 sparkling bottle this week = $\frac{5}{4}=\$1.25$

The cost of 1 sparkling bottle in this week is less than last week, so we pay less this week.

For finding how much we pay less this week, we have to subtract cost of 1 sparkling bottle this week from cost of 1 sparkling bottle last week.

Framing the above sentence in equation form, we get;

$Amount\ of\ money\ we\ pay\ less=1.69-1.25=\$0.44$

Hence we pay $0.44 less this week.

8 0

3 years ago

What is the slope of the line through (6,0) and (7,1)

monitta

$\huge \bf༆ Answer ༄$

Let's find the slope of line passing through given points ~

$\sf \dfrac{y2 - y}{x2 - x1}$

$\sf \dfrac{1 - 0}{7 - 6}$

$\sf \dfrac{1}{1}$

$\sf1$

Hence, slope of the line will be 1.

7 0

2 years ago

Read 2 more answers

*20 POINTS*

Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6 (all prime factors of constant term)

Q: ±1, ±7 (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7 (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

112+72-164-26+6 = 0 OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7 -9 -41 13 6

-14 46 -10 -6

7 -23 5 3 0 The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial. Try f(3):

f(3)=7(27)-23(9)+5(3)+3

189-207+15+3 = 0 OK!! we found another zero at x=3

Now, another synthetic division:

3⊥ 7 -23 5 3

21 -6 -3_

7 -2 -1 0

The quotient is a quadratic polynomial:

7x2-2x-1 This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0

3 years ago

Solve the initial value problem. dy/dt = 1 + 6/t , t > 0, y = 8 when t = 1

nordsb [41]

$\displaystyle\frac{dy}{dt} = 1 + \frac{6}{t}\ \Rightarrow\ dy = \left( 1 + \frac{6}{t}\right) dt\ \Rightarrow\int 1\, dy = \int \left( 1 + \frac{6}{t}\right) dt \ \Rightarrow \\ \\
y = t + 6\ln|t| + C. \text{ But $t\ \textgreater \ 0$ so }y = t + 6\ln t + C. \\ \\ 
y(1) = 8\ \Rightarrow\ 8 = 1 + 6 \ln 1 + C \ \Rightarrow\ C = 7 \text{ so } \\ \\
y(t) = t + 6\ln t + 7$

5 0

3 years ago

Find all real solutions of this equation to answer the question. (6 – 2x)(3 – 2x)x = 40

Vika [28.1K]

<span>No. Its x=4. You couldn't cut the box to much lower without it being absurd.
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</span>

5 0

3 years ago

Read 2 more answers