![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
![x^ \frac{1}{2}= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20%20)
times that by 4
4√x
STEP 1) 7x+10x+12x= 232 STEP 2) 29x = 232 STEP 3) divide 232 by 29 STEP 4) x=8 STEP 5) 7 times 8 = 56, 10 times 8 = 80, 12 times 8 = 96. the highest score was a 96
36v - 12 = 12 .....add 12 to both sides
36v - 12 + 12 = 12 + 12...simplify
36v = 24...divide both sides by 36
(36/36)v = 24/36
v = 2/3 <===
Answer:
im gonna guess that the problem is 2x+13-9y, the answer is 38
Answer:
29
Just replace n by 8 ===> C(8) = -6+5(8-1) = - 6 + 5x7 = -6+35 = 29
Step-by-step explanation:
We have been given a sequence formula. We are asked to find the 8th term of our given sequence.
We know that an arithmetic sequence is in form A_n=a_1+(n-1)d, where,
A_n=\text{ nth term of sequence},
A_1=\text{ 1st term of sequence},
n = Number of terms in sequence,
d = Common difference.
To find the 8th term of our given sequence, we will substitute n=8 in our given formula.
c(n)=-6+5(n-1)
c(8)=-6+5(8-1)
c(8)=-6+5(7)
c(8)=-6+35
