The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
So first I hope this helps! But from what I’ve learned in school is that a unit rate pretty much just mean *1... so in words the answers would be 1/6 and hour for every 2/23 miles
60*80-10*16 if it's regular area and not surface area
If you flip a coin one time, the probability to get a Head is
p = 1/2
The probability of not getting a head in a single toss is :
q = 1 - 1/2 = 1/2
Thus there is only one unique situation to get the same number of heads and tails : in 10 toss you need to get exactly five heads, it will means that the rest is the tails.
Now using Binomial theorem of probability, the probability of getting exactly x = 5 heads in a total of n = 10 tosses is :
P(X = 5) =
≈ 0.246
So the probability of that is 24,6 %
Good Luck
Cross multiply the denominators by the numerators. In other words, 12 times 3 and 7 times x (x, being our missing number).
We end up with 36 and 7x.
Divide both sides by 7.
36/7x = 5.14
x = 5.14
Hope this helps!