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2 years ago

Find the slope of the line through each pair of points (20,-16),(19-16)

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

7 0

Answer:

Slope = 0

This line is not sloped. It moves flat relative to the x axis.

Step-by-step explanation:

Slope = (y2 - y1) / (x2 - x1)

= (-16 - (-16)) / (19 - 20)

= (-16 + 16) / (-1)

= 0 / -1

= 0

ale4655 [162]2 years ago

3 0

Answer:

Undefined slope.

Step-by-step explanation:

The formula should be y2 - y1 over x2 - x1

Points ( 20,-16 ) and ( 19, -16 )

So ( -16 - ( -16 ) ) over ( 19 - 20 )

0 over -1

The slope is 0. Undefined.

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Find the volume of the figure. Round to 3 decimal places.

Digiron [165]

Answer:

v= 360

Step-by-step explanation:

v= ( l w h) / 3

v= ( 12 * 6 * 15 ) / 3

v = 1080/ 3

v=360

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2 years ago

Solve for k. 7k - 2 ≥ -9

Akimi4 [234]

Answer: k ≥ -1

Step-by-step explanation:

7k - 2 ≥ -9

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3 years ago

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Find the value or values of x in the quadratic equation x2=6x-9.

ozzi

x² = 6x - 9, or x² - 6x + 9 = 0, or x² - 2*x*3 + 3² = 0, or (x-3)² = 0 => x₁ = x₂ = 3.

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3 years ago

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One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t

kozerog [31]

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function $f(x) = x^3-8x^2 + 17x-10$ is $(x-5).$

Factor the polynomial in the following way:

$x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)$

Now factor the quadratic in brackets:

$x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)$

Hence,

$f(x)=(x-5)(x-2)(x-1)$

The x-intercepts are points at which y = 0, so

$(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1$

The y-intercepts are points at which x = 0, so

$y=0^3-8\cdot 0^2+17\cdot 0-10=-10$

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3 years ago

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The Volume of the cone shown is 6 cubic inches. What is the height of a cone with the same base diameter but a volume of only 3

Viefleur [7K]

We know that
[volume of the cone]=(1/3)*area of the base*height
h-----> height
AB-----> area of the base
so
[volume of the original cone]=(1/3)*AB*h
volume=6 in³
(1/3)*AB*h=6--------> h=18/AB

For a cone with the same base diameter but a volume of only 3 cubic inches
(1/3)*AB*h=3 in³-------> h=9*AB

the answer is
The new cone height is half the original height

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3 years ago