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3 years ago

Select all the expressions that will represent a rational number, without simplifying.

Mathematics

1 answer:

Afina-wow [57]3 years ago

5 0

ANSWER:

Use math websites

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A coyote population has decreased by 168 over the past 3 years. The same number of coyotes were lost each year. Which division e

a_sh-v [17]

Answer:

C, $\frac{-168}{3}$

Step-by-step explanation:

The number of coyotes is decreasing, which makes it negative, but you can't have a negative year, so the answer must be $\frac{-168}{3}$

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3 years ago

What is the first term of the polynomial Raj ended up with? 6x3 8x3 2xy2 3xy2

laila [671]

The polynomial is a third degree polynomial with x and y terms so when written in standard form x comes before y and the x^3 is going to be the first term. The first term of this polynomial is 8x^3, aka the second answer choice.

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3 years ago

The expression 7 + 2(x – 3) + 5x is simplified correctly in the correct order. Which of the steps has an incorrect justification

timama [110]

7 + 2(x - 3) + 5x

= 7 + 2x - 6 + 5x distributed 2 into x - 3

= 7 - 6 + 2x + 5x grouped like terms together

= 1 + 7x

You didn't provide an image of the steps but hopefully you can figure it out based on the information I provided.

6 0

4 years ago

Read 2 more answers

Two sides of a triangle have lengths 6 cm and 6cm describe the possible lengths of the third side

Rashid [163]

Answer:

0 < x < 12

Step-by-step explanation:

Since it's given that side a and side b both have a length of 6, side c has to be 0 < x < 12.

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3 years ago

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

3 years ago