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Darya [45]
3 years ago
8

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y - 4 = 1/4(x- 8). What

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Hi! I'm happy to help!

Point slope form states that y-y_{1}=m(x-x_{1}). m represents your slope (rise/run) and y_{1} and x_{1} represent your first y and x points, and y and x represent your second y and x points. We already have our equation here:

y - 4 = 1/4(x- 8)

Now, let's dive into what slope-intercept form is. Slope intercept form states that y=mx+b. m represents our slope, b represents our y intercept, y represents a y point, and x represents the corresponding x point.

Since we know our m, we can solve for b, by using our other numbers. Let's use our first set of coordinates.

4=1/4(8)+b

4=2+b

2=b

Now our second set to double check:

2=1/4(0)+b

2=0+b

2=b

We know that b must equal 2, so our equation must be y=1/4x+2, which is  option 3.

<u>You should pick option 3.</u>

<u>(y-intercept is where the line hits the y-axis(when x=0). We could've used our second coordinates (0,2), where x equals 0 to know that 2 is the y-intercept (b). This shortcut only works on specific problems though.)</u>

I hope this was helpful, keep learning! :D

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Yuliya22 [10]
To find concavity we need to find the second derivative.
Use quotient rule to find f'(x)=4/(x+3)^2
Then use chain rule to find f''(x)=-8/(x+3)^3
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4 years ago
A family has three children. Using b to stand for a boy and g for girl give the following.(To indicate that the first child is a
zubka84 [21]

Answer:

3/8 and 3/5

Step-by-step explanation:

Given that a family has three children. Using b to stand for a boy and g for girl give the following we can write sample space for a family having three children as

(bbb, bbg, bgg, bgb, gbb, gbg, ggb, ggg)

E - exactly two boys

Sample space count = 8

Exactly two boys count = 3

a) p(E) = \frac{3}{8}

b) odds for E is probability/1-probability

= \frac{3}{5}

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There are three containers filled with different gases as shown.
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\qquad\qquad\huge\underline{{\sf Answer}}

As we know,

\sf \qquad density =  \dfrac{mass}{volume}

So, we can infer that :

\sf \qquad mass= {density} \cdot{volume}

Now, let's calculate the mass of gases in each case :

<h3>Case A : Hydrogen ~</h3>

\qquad \sf  \dashrightarrow \:mass = 0.09 \times (15) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.09 \times 3375 {}^{}

\qquad \sf  \dashrightarrow \:mass = 303.75 \:  \: mg {}^{}

or

\qquad \sf  \dashrightarrow \:mass =0. 30375 \:  \: g {}^{}

<h3>Case B : Helium ~ </h3>

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: (14 \sdot 12 \sdot10)

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 1680

\qquad \sf  \dashrightarrow \:mass =0. 175 \:  \cdot  \: 294 \: \:  mg

or

\qquad \sf  \dashrightarrow \:mass = 0.294 \:  \: g

<h3>Case C : Nitrogen ~ </h3>

\qquad \sf  \dashrightarrow \:mass = 1.251\:  \cdot  \: \dfrac{4}{3}  \cdot3.14 \cdot(4) {}^{3}

\qquad \sf  \dashrightarrow \:mass = 0.417\:  \cdot  \: 803.84

\qquad \sf  \dashrightarrow \:mass = 335.201 \:  \: mg

or

\qquad \sf  \dashrightarrow \:mass = 0.335 \:  \: g

So, the arrangement of masses from least to greatest is :

  • (1.) Hydrogen < (2.) Helium < (3.) Nitrogen
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