Question

Obtain the backward difference for the function f(x) =x^3 from x=1 to 1.05​

Answer 1

Answer:

2.4

Step-by-step explanation:

hope it helps you......

Answer 2

We have to find integration of f(x) having upper limit 1.05 and lower limit 1

$\\ \rm\longmapsto \displaystyle{\int^{1.05}_1}x^3dx$

$\\ \rm\longmapsto \left[\dfrac{3x^{3+1}}{3+1}\right]^{1.05}_1$

$\\ \rm\longmapsto \left[\dfrac{3x^4}{4}\right]^{1.05}_1$

$\\ \rm\longmapsto \dfrac{3(1.05)^4-3(1)^4}{4}$

$\\ \rm\longmapsto \dfrac{3(1.2)-3(1)}{4}$

$\\ \rm\longmapsto \dfrac{3.6-3}{4}$

$\\ \rm\longmapsto \dfrac{0.6}{4}$

$\\ \rm\longmapsto 2.4$