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Novay_Z [31]
3 years ago
13

Is 6 over 3 an irrational number

Mathematics
1 answer:
vitfil [10]3 years ago
7 0

Answer:

No, you've already proven it's not irrational by writing it as 6/3.  You get 2.  

Step-by-step explanation:

An irrational number is any number that cannot be written as a fraction.

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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
2 years ago
Someone help me please with this algebra problem
aleksandr82 [10.1K]

Answer:

4

Step-by-step explanation:

3r = 10 + 5s

r = 10

3(10) = 10 + 5s

30 = 10 + 5r

20 = 5r

r = 4

7 0
3 years ago
A farm has chickens and cows. All the cows have 4 legs and all the chickens have 2 legs.
lora16 [44]

Answer:

21 chickens

Step-by-step explanation:

10×4=40

82-40=42

42÷2=21

3 0
3 years ago
A farmer wants to fence an area of 13.5 million square feet in a rectangular field and then divide it in half with a fence paral
denis23 [38]

Answer:

  F = 3x +(2.7×10^7)/x

Step-by-step explanation:

The formulas for area and perimeter of a rectangle can be used to find the desired function.

<h3>Area</h3>

The area of the rectangle will be the product of its dimensions:

  A = LW

Using the given values, we have ...

  13.5×10^6 = xy

Solving for y gives ...

  y = (13.5×10^6)/x

<h3>Perimeter</h3>

The perimeter of the rectangle is the sum of the side lengths:

  P = 2(L+W) = 2(x+y)

<h3>Fence length</h3>

The total amount of fence required is the perimeter plus one more section that is x feet long.

  F = 2(x +y) +x = 3x +2y

Substituting for y, we have a function of x:

  F = 3x +(2.7×10^7)/x

__

<em>Additional comment</em>

The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.

4 0
2 years ago
HELP ASAP PLEASE!!!
sasho [114]
Y=x^3+5
y^-1=....
example >>a=x^3+5
a-5=x^3
3√a-5=x
y^-1=3√x-5
3 0
3 years ago
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