Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
Add all the numbers to get 36 and divide by the amount of numbers to get your answer. 6.
Answer:
12.56 units
Step-by-step explanation:
C=pid
C = 3.14(4)
C = 12.56
Answer:
60 yd
Step-by-step explanation:
Volume is length x width x height. Therefore in this case, we do 4x3x5 which turns out to be 60. Also don't forget to add yd after your answer because this is measured in yards.
Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
