Y-3=-2(x-5)
y-3=-2x+10
y=-2x+13
hope this helps :)
(−m)(n)p(3m−5n+7p)
=((−m)(n)p)(3m+−5n+7p)
=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)
=−3m^2np+5mn^2p−7mnp^2
Answer:
B. 0.03110
Step-by-step explanation:
Given
Probability of Hit = 60%
Required
Determine the probability that he misses at 6th throw
Represent Probability of Hit with P
![P = 60\%](https://tex.z-dn.net/?f=P%20%3D%2060%5C%25)
Convert to decimal
![P = 0,6](https://tex.z-dn.net/?f=P%20%3D%200%2C6)
Next; Determine the Probability of Miss (q)
Opposite probabilities add up to 1;
So,
![p + q = 1](https://tex.z-dn.net/?f=p%20%2B%20q%20%3D%201)
![q = 1 - p](https://tex.z-dn.net/?f=q%20%3D%201%20-%20p)
Substitute 0.6 for p
![q = 1 - 0.6](https://tex.z-dn.net/?f=q%20%3D%201%20-%200.6)
![q = 0.4](https://tex.z-dn.net/?f=q%20%3D%200.4)
Next,is to determine the required probability;
Since, he's expected to miss the 6th throw, the probability is:
![Probability = p^5 * q](https://tex.z-dn.net/?f=Probability%20%3D%20p%5E5%20%2A%20q)
![Probability = 0.6^5 * 0.4](https://tex.z-dn.net/?f=Probability%20%3D%200.6%5E5%20%2A%200.4)
![Probability = 0.031104](https://tex.z-dn.net/?f=Probability%20%3D%200.031104)
Hence;
<em>Option B answers the question</em>
Answer:
$10668.67
Step-by-step explanation:
If the car value goes down 16% each year, after the first year, it will be worth 1520.
The next year, it will be worth $12700.80
After the third year, the car will be worth $10,668.67
5 1/3, 5 2/3, 6. And that's about it!