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enot [183]
3 years ago
6

Weekly demand for a product is normally distributed with a mean and standard deviation of 3,211 and 484 units, respectively. Wha

t is the probability that weekly demand exceeds 4,044
Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

The probability it is greater than or equal to 0.95 and less than or equal to 0.96

Step-by-step explanation:

In order to calculate the probability that weekly demand exceeds 4,044 we would have to calculate the z value as follows:

Z= (X-mean)/standard deviation

Z= (4044 - 3211)/484

Z=1.721

So, looking for standard normal distribution table 1.7 from row, we get values from 0.9554 till 0.9633, for column 0.02 it is 0.9573

Therefore, the probability it is greater than or equal to 0.95 and less than or equal to 0.96

You might be interested in
Sand for use on icy roads is stored in a conical pile 14.2 m high and with a base diameter of 34.4 m calculate the volume of the
sammy [17]

Answer:

1. The volume of the pile is 4,399.7719 m^3

2. The number of sanders to be filled from a pile is 638

Step-by-step explanation:

Here, we firstly would calculate the volume of the pile

Mathematically, that will be;

V = 1/3 * pi * r^2 * h

from the question, h = 14.2

Mathematically, r = d/2

r = 34.4/2 = 17.2 m

So the volume will be:

V = 1/3 * 3.142 * 17.2^2 * 14.2

V = 4,399.7719 m^3

To find the number of sanders to be filled,

we simply divide the volume obtained by the volume a sander can take

That will be;

4,399.7719/6.9

= 637.6 which is 638

4 0
2 years ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
100 decreased by a<br> number k equals 44
Arte-miy333 [17]

Answer:

56

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Use the base ten system and mental math to find the products. of 40x50=
Fantom [35]

Answer:

2000

Step-by-step explanation:

(4x5) x 100

4 0
3 years ago
Read 2 more answers
2(3x + 5) = 9x + 9 - 3x + 1​
ELEN [110]
2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.
3 0
3 years ago
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