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lawyer [7]
3 years ago
13

How is (8×10,000)+(4×10)+(5×0.01)+(2×1) in standard form?

Mathematics
2 answers:
torisob [31]3 years ago
7 0

Answer:

80042.05

Step-by-step explanation:

(8×10,000)+(4×10)+(5×0.01)+(2×1)

80000 +40 +.05 +2

Putting the numbers in decreasing place value

80000+40 +2 +.05

80042.05

LUCKY_DIMON [66]3 years ago
6 0

Eight x ten thousand plus four plus ten plus 5 times zero point zero one plus 2 times 1 Lol

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Copy down the calculation below and insert one pair of brackets so that the
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Answer:

12+24÷(2^2+8)

Step-by-step explanation:

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7 0
2 years ago
what percent of 150 is 96? .64% 6.4% 156% 64% find 225% of 3.6. 810 8.1 81 .81 135% of t is 63. t = 46.67 t = 85.05 t = 850.5 t
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1.To find the percentage of 150 is 96 you do:96 divided by 150 multiply by 100=64%
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4 years ago
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4 years ago
How do I do 1.5 divided by -2.5?
Goryan [66]
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4 years ago
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Which choice below is a boxplot for the following distribution? 67, 66, 64, 62, 60, 56, 54, 50, 46, 42, 41, 40, 40, 38, 35, 21,
luda_lava [24]

Answer:

Option E - Box plot E

Step-by-step explanation:

Given : Data,

67, 66, 64, 62, 60, 56, 54, 50, 46, 42, 41, 40, 40, 38, 35, 21, 19

To find : Which choice below is a boxplot for the following distribution?

Solution :

Step 1- Arranging the data from lowest to highest,

{19,21,35,38,40,40,41,42,46,50,54,56,60,62,64,66,67}  

Step 2 - Find the median of the data  

As the data is odd numbers so the median is \frac{n+1}{2} th term.

\frac{n+1}{2}=\frac{17+1}{2}=9th term.

9th term is 46

∴ Q_2=46  

Step 3 - To find Upper quartile and lower quartile  

Lower quartile data set is the median of the upper terms from median

{19,21,35,38,40,40,41,42}

Median of the set is M=\frac{38+40}{2}=39

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Upper quartile data set is the median of the lower terms from median

{ 50,54,56,60,62,64,66,67}

Median of the set is M=\frac{60+62}{2}=61

∴ Q_3=61  

We have plot the box plot attached below.

Our box plot is matched with Box plot E.

Therefore, Option E is correct.

8 0
3 years ago
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