Given:
First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.
Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.
At this point she had sold all her eggs.
To find:
The number of egg the lady have when she came to the market.
Solution:
Let x be the number of egg that the lady have when she came to the market.
First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg. So, the number of remining egg after second customer is





At this point she had sold all her eggs. It means the remining eggs is 0.


Multiply both sides by 4.

Therefore, the lady came to the market is with 3 eggs.
54/x = 6...multiply both sides by x
54 = 6x...divide both sides by 6
54/6 = x
9 = x
This is not an arithmetic sequence.
It does not go up or down by the same amount each time.
It is a geometric sequence
it is multiplied by 5 each time
<span>C.) y = 850(1.05)^x
It should be exponential grow.</span>
Well this is kind of difficult because we have no way to determine a constant for each banana; however, we can still formulate an equation to form some sort of solution.

Divide both sides by two:

Now, we can continue to go forward as long as know how many pounds each banana bunch weighs and how many bananas are in the bunch.
We could say there are "x" bananas in each pound of bananas:

Or:

Or to isolate "c":