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konstantin123 [22]
2 years ago
9

The perimeter of a triangle is 30 units. If it is dilated with respect to origin by a scale factor of 0.5, what is the perimeter

of the resulting triangle? ОА. 30 units ОВ. 20 units Ос. . 15 units OD 7 5 units​
Mathematics
2 answers:
Feliz [49]2 years ago
7 0

Answer:

15 units. Hope that helps:) Please give me brainliest:) Please...

Step-by-step explanation:

gulaghasi [49]2 years ago
3 0

Answer:

a

Step-by-step explanation:

a

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Answer:

Guo Qi requires 75 days to watch videos on Khan Academy.

Step-by-step explanation:

We are given the following in the question:

Number of videos watched by Guo Qi each day = 15

Average length of each video = 8 minutes

Total minutes of video = 9000 minutes

Total number of videos to be watched =

=\dfrac{\text{Total minutes}}{\text{Average length of video}}\\\\=\dfrac{9000}{8}=1125

Guo Qi needs to watch 1125 videos.

Number of days required =

=\dfrac{\text{Total number of videos}}{\text{Videos watched in one day}}\\\\=\dfrac{1125}{15}=75

Guo Qi requires 75 days to watch videos on Khan Academy.

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3 years ago
If f(x) = _4x _ 1, find f(_2)
tia_tia [17]
The answer is 7

f(x) = -4x - 1
f(-2) = ?

Since f(x) = f(-2), then x = -2. Now just substitute x in the function:
f(-2) = (-4) * (-2) - 1
f(-2) = 8 - 1
f(-2) = 7
8 0
3 years ago
$47 tie; 4.5% markup
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Find the distance between the points J(−8, 0) and K(1, 4).
Tasya [4]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Read 2 more answers
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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3 years ago
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