Answer:
x stays x in both equations so x stands for x
Step-by-step explanation:
y=3x+6
you can put this into a graphing caculator or draw it yourself.
6 is the y value when x equals 0. and the 3 represents the slope so then it is solved for any y value
Answer:
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Step-by-step explanation:////
Answer:
a) 
b) 
c) 
d) 
e) The intersection between the set A and B is the element c so then we have this:

Step-by-step explanation:
We have the following space provided:
![S= [a,b,c,d,e]](https://tex.z-dn.net/?f=%20S%3D%20%5Ba%2Cb%2Cc%2Cd%2Ce%5D)
With the following probabilities:

And we define the following events:
A= [a,b,c], B=[c,d,e]
For this case we can find the individual probabilities for A and B like this:


Determine:
a. P(A)

b. P(B)

c. P(A’)
From definition of complement we have this:

d. P(AUB)
Using the total law of probability we got:

For this case
, so if we replace we got:

e. P(AnB)
The intersection between the set A and B is the element c so then we have this:

the standard form is 83,902 & the expanded form is 83,000+900+2